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```integer(3)	       Perl Programmers	Reference Guide		    integer(3)

NAME
integer - Perl pragma to	use integer arithmetic instead of floating
point

SYNOPSIS
use integer;
\$x =	10/3;
# \$x	is now 3, not 3.33333333333333333

DESCRIPTION
This tells the compiler to use integer operations from here to the end
of the enclosing	BLOCK.	On many	machines, this doesn't matter a	great
deal for	most computations, but on those	without	floating point
hardware, it can	make a big difference in performance.

Note that this only affects how most of the arithmetic and relational
operators handle	their operands and results, and	not how	all numbers
everywhere are treated.	Specifically, "use integer;" has the effect
that before computing the results of the	arithmetic operators (+, -, *,
/, %, +=, -=, *=, /=, %=, and unary minus), the comparison operators
(<, <=, >, >=, ==, !=, <=>), and	the bitwise operators (|, &, ^,	<<,
>>, |=, &=, ^=, <<=, >>=), the operands have their fractional portions
truncated (or floored), and the result will have	its fractional portion
truncated as well.  In addition,	the range of operands and results is
restricted to that of familiar two's complement integers, i.e.,
-(2**31)	.. (2**31-1) on	32-bit architectures, and -(2**63) ..
(2**63-1) on 64-bit architectures.  For example,	this code

use integer;
\$x =	5.8;
\$y =	2.5;
\$z =	2.7;
\$a =	2**31 -	1;  # Largest positive integer on 32-bit machines
\$, =	", ";
print \$x, -\$x, \$x+\$y, \$x-\$y,	\$x/\$y, \$x*\$y, \$y==\$z, \$a, \$a+1;

will print:  5.8, -5, 7,	3, 2, 10, 1, 2147483647, -2147483648

Note that \$x is still printed as	having its true	non-integer value of
5.8 since it wasn't operated on.	 And note too the wrap-around from the
largest positive	integer	to the largest negative	one.   Also, arguments
passed to functions and the values returned by them are not affected by
"use integer;".	E.g.,

srand(1.5);
\$, =	", ";
print sin(.5), cos(.5), atan2(1,2), sqrt(2),	rand(10);

will give the same result with or without "use integer;"	 The power
operator	"**" is	also not affected, so that 2 **	.5 is always the
square root of 2.  Now, it so happens that the pre- and post- increment
and decrement operators,	++ and --, are not affected by "use integer;"
either.	Some may rightly consider this to be a bug -- but at least
it's a long-standing one.

Finally,	"use integer;" also has	an additional affect on	the bitwise
operators.  Normally, the operands and results are treated as unsigned
integers, but with "use integer;" the operands and results are signed.
This means, among other things, that ~0 is -1, and -2 & -5 is -6.

Internally, native integer arithmetic (as provided by your C compiler)
is used.	 This means that Perl's	own semantics for arithmetic
operations may not be preserved.	 One common source of trouble is the
modulus of negative numbers, which Perl does one	way, but your hardware
may do another.

% perl -le 'print (4	% -3)'
-2
% perl -Minteger -le	'print (4 % -3)'
1

See "Pragmatic Modules" in perlmodlib, "Integer Arithmetic" in perlop

perl v5.26.0			  2017-04-19			    integer(3)
```

NAME | SYNOPSIS | DESCRIPTION

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