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integer(3)	       Perl Programmers	Reference Guide		    integer(3)

NAME
       integer - Perl pragma to	use integer arithmetic instead of floating
       point

SYNOPSIS
	   use integer;
	   $x =	10/3;
	   # $x	is now 3, not 3.33333333333333333

DESCRIPTION
       This tells the compiler to use integer operations from here to the end
       of the enclosing	BLOCK.	On many	machines, this doesn't matter a	great
       deal for	most computations, but on those	without	floating point
       hardware, it can	make a big difference in performance.

       Note that this only affects how most of the arithmetic and relational
       operators handle	their operands and results, and	not how	all numbers
       everywhere are treated.	Specifically, "use integer;" has the effect
       that before computing the results of the	arithmetic operators (+, -, *,
       /, %, +=, -=, *=, /=, %=, and unary minus), the comparison operators
       (<, <=, >, >=, ==, !=, <=>), and	the bitwise operators (|, &, ^,	<<,
       >>, |=, &=, ^=, <<=, >>=), the operands have their fractional portions
       truncated (or floored), and the result will have	its fractional portion
       truncated as well.  In addition,	the range of operands and results is
       restricted to that of familiar two's complement integers, i.e.,
       -(2**31)	.. (2**31-1) on	32-bit architectures, and -(2**63) ..
       (2**63-1) on 64-bit architectures.  For example,	this code

	   use integer;
	   $x =	5.8;
	   $y =	2.5;
	   $z =	2.7;
	   $a =	2**31 -	1;  # Largest positive integer on 32-bit machines
	   $, =	", ";
	   print $x, -$x, $x+$y, $x-$y,	$x/$y, $x*$y, $y==$z, $a, $a+1;

       will print:  5.8, -5, 7,	3, 2, 10, 1, 2147483647, -2147483648

       Note that $x is still printed as	having its true	non-integer value of
       5.8 since it wasn't operated on.	 And note too the wrap-around from the
       largest positive	integer	to the largest negative	one.   Also, arguments
       passed to functions and the values returned by them are not affected by
       "use integer;".	E.g.,

	   srand(1.5);
	   $, =	", ";
	   print sin(.5), cos(.5), atan2(1,2), sqrt(2),	rand(10);

       will give the same result with or without "use integer;"	 The power
       operator	"**" is	also not affected, so that 2 **	.5 is always the
       square root of 2.  Now, it so happens that the pre- and post- increment
       and decrement operators,	++ and --, are not affected by "use integer;"
       either.	Some may rightly consider this to be a bug -- but at least
       it's a long-standing one.

       Finally,	"use integer;" also has	an additional affect on	the bitwise
       operators.  Normally, the operands and results are treated as unsigned
       integers, but with "use integer;" the operands and results are signed.
       This means, among other things, that ~0 is -1, and -2 & -5 is -6.

       Internally, native integer arithmetic (as provided by your C compiler)
       is used.	 This means that Perl's	own semantics for arithmetic
       operations may not be preserved.	 One common source of trouble is the
       modulus of negative numbers, which Perl does one	way, but your hardware
       may do another.

	   % perl -le 'print (4	% -3)'
	   -2
	   % perl -Minteger -le	'print (4 % -3)'
	   1

       See "Pragmatic Modules" in perlmodlib, "Integer Arithmetic" in perlop

perl v5.26.0			  2017-04-19			    integer(3)

NAME | SYNOPSIS | DESCRIPTION

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